Percentage SET: Q16-Q20
Solution: 2
Let the original price of the sugar per kg be Rs. X. Let the quantity of sugar purchased initially be Y units in Rs. 270.
Thus, X × Y = 270 ….(1)
Given: Price of sugar decreased by 10%.
∴New price of sugar per Kg
= 0.9X
Since the man could buy 1 more kg on his reduction of price, hence
⇒ Quantity of sugar purchased = Y + 1
As the total expenditure remains the same i.e. Rs. 270, therefore
⇒ 0.9X × (Y + 1) = 270 …(2)
Dividing equation (1) by (2), we get
⇒ Y = 0.9Y + 0.9
⇒ Y = 9 units
∴ From equation (1) we get, X = Rs. 30
10% = 1
100% = 10 kg final
but he buy = 10 - 1 = 9kg original
9 kg = Rs.270
1 kg = Rs.30
Solution: 3
Let the total number of votes in the election be ‘x’, then,
According to the question, one candidate got 65% of votes which was 520 votes.
⇒ x × (65/100) = 520
⇒ x = 520 × (100/65) = 800
∴ Total number of votes in the election was 800.Solution: 3
Given,
50% of (x – y) = 30% of (x + y)
⇒ (50/100) (x – y) = (30/100) (x + y)
⇒ 5(x – y) = 3(x + y)
⇒ 5x – 3x = 3y + 5y
⇒ 2x = 8y
⇒ x = 4y
∴ Required per cent
⇒ (y/x) × 100%
⇒ (y/4y) × 100%
⇒ (1/4) × 100%
⇒ 25%19. After selling 5% of a quantity of sugar, 5 Kgs of sugar remains. Find the total quantity of sugar?
Solution: 2
According to the given question
Let the total sugar be ‘x’ kg
95% of total sugar = 5kg
Therefore,
95/100 × x = 5
x = 5 × 100/95
x = 5.26 kg
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